Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1101000000100011111101 |
3 | 1201102200212102202012021112 |
4 | 2332311133031000203331 |
5 | 3204330220343303011 |
6 | 43520314350011405 |
7 | 2522315266114355 |
oct | 276653715004375 |
9 | 51380772665245 |
10 | 13114132400381 |
11 | 41a6743945431 |
12 | 15797344a6b65 |
13 | 741871352c3c |
14 | 334a27d85b65 |
15 | 17b1de45958b |
hex | bed5f3408fd |
13114132400381 has 2 divisors, whose sum is σ = 13114132400382. Its totient is φ = 13114132400380.
The previous prime is 13114132400311. The next prime is 13114132400419. The reversal of 13114132400381 is 18300423141131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11474925901156 + 1639206499225 = 3387466^2 + 1280315^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114132400381 is a prime.
It is a super-2 number, since 2×131141324003812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114132400311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066200190 + 6557066200191.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066200191).
Almost surely, 213114132400381 is an apocalyptic number.
It is an amenable number.
13114132400381 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114132400381 is an equidigital number, since it uses as much as digits as its factorization.
13114132400381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 13114132400381 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thousand, three hundred eighty-one".
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