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13114132400419 is a prime number
BaseRepresentation
bin1011111011010101111100…
…1101000000100100100011
31201102200212102202012022221
42332311133031000210203
53204330220343303134
643520314350011511
72522315266114441
oct276653715004443
951380772665287
1013114132400419
1141a6743945466
1215797344a6b97
13741871352c6b
14334a27d85b91
1517b1de4595b4
hexbed5f340923

13114132400419 has 2 divisors, whose sum is σ = 13114132400420. Its totient is φ = 13114132400418.

The previous prime is 13114132400381. The next prime is 13114132400443. The reversal of 13114132400419 is 91400423141131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13114132400419 - 213 = 13114132392227 is a prime.

It is a super-2 number, since 2×131141324004192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13114132400119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066200209 + 6557066200210.

It is an arithmetic number, because the mean of its divisors is an integer number (6557066200210).

Almost surely, 213114132400419 is an apocalyptic number.

13114132400419 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114132400419 is an equidigital number, since it uses as much as digits as its factorization.

13114132400419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 34.

The spelling of 13114132400419 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thousand, four hundred nineteen".