Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …100100000000100010111 |
3 | 11122100222122101010021222 |
4 | 103011112110200010113 |
5 | 132441233242140322 |
6 | 2442242133000555 |
7 | 163514020421666 |
oct | 23052624400427 |
9 | 4570878333258 |
10 | 1311413240087 |
11 | 466192649415 |
12 | 1921b178315b |
13 | 9688681a942 |
14 | 476892a8ddd |
15 | 241a5de0e42 |
hex | 13156520117 |
1311413240087 has 2 divisors, whose sum is σ = 1311413240088. Its totient is φ = 1311413240086.
The previous prime is 1311413240029. The next prime is 1311413240099. The reversal of 1311413240087 is 7800423141131.
It is a strong prime.
It is an emirp because it is prime and its reverse (7800423141131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311413240087 - 236 = 1242693763351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311413240017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655706620043 + 655706620044.
It is an arithmetic number, because the mean of its divisors is an integer number (655706620044).
Almost surely, 21311413240087 is an apocalyptic number.
1311413240087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311413240087 is an equidigital number, since it uses as much as digits as its factorization.
1311413240087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 1311413240087 in words is "one trillion, three hundred eleven billion, four hundred thirteen million, two hundred forty thousand, eighty-seven".
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