Base | Representation |
---|---|
bin | 11101110100010110111000… |
… | …000010000111110111011100 |
3 | 122012022222200100111102102022 |
4 | 131310112320002013313130 |
5 | 114142104412421404040 |
6 | 1142525254220315312 |
7 | 36423435155562206 |
oct | 3564267002076734 |
9 | 565288610442368 |
10 | 131141324013020 |
11 | 388707a56158a2 |
12 | 128600980a2b38 |
13 | 582375c807869 |
14 | 24553b9a05776 |
15 | 1026447db66b5 |
hex | 7745b8087ddc |
131141324013020 has 96 divisors (see below), whose sum is σ = 283159347609600. Its totient is φ = 50981163851520.
The previous prime is 131141324013019. The next prime is 131141324013101. The reversal of 131141324013020 is 20310423141131.
It is a super-4 number, since 4×1311413240130204 (a number of 58 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7451626181 + ... + 7451643779.
It is an arithmetic number, because the mean of its divisors is an integer number (2949576537600).
Almost surely, 2131141324013020 is an apocalyptic number.
131141324013020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131141324013020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (141579673804800).
131141324013020 is an abundant number, since it is smaller than the sum of its proper divisors (152018023596580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141324013020 is a wasteful number, since it uses less digits than its factorization.
131141324013020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28443 (or 28441 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 131141324013020 its reverse (20310423141131), we get a palindrome (151451747154151).
The spelling of 131141324013020 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, twenty".
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