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13114132420201 is a prime number
BaseRepresentation
bin1011111011010101111100…
…1101000101011001101001
31201102200212102210012110121
42332311133031011121221
53204330220344421301
643520314350243241
72522315266226221
oct276653715053151
951380772705417
1013114132420201
1141a674395930a
1215797344b6521
1374187135bc77
14334a27d8d081
1517b1de4603a1
hexbed5f345669

13114132420201 has 2 divisors, whose sum is σ = 13114132420202. Its totient is φ = 13114132420200.

The previous prime is 13114132420199. The next prime is 13114132420231. The reversal of 13114132420201 is 10202423141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12553019064576 + 561113355625 = 3543024^2 + 749075^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114132420201 - 21 = 13114132420199 is a prime.

Together with 13114132420199, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13114132420231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066210100 + 6557066210101.

It is an arithmetic number, because the mean of its divisors is an integer number (6557066210101).

Almost surely, 213114132420201 is an apocalyptic number.

It is an amenable number.

13114132420201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114132420201 is an equidigital number, since it uses as much as digits as its factorization.

13114132420201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13114132420201 its reverse (10202423141131), we get a palindrome (23316555561332).

The spelling of 13114132420201 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred twenty thousand, two hundred one".