Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1101000101011010000111 |
3 | 1201102200212102210012111201 |
4 | 2332311133031011122013 |
5 | 3204330220344421411 |
6 | 43520314350243331 |
7 | 2522315266226263 |
oct | 276653715053207 |
9 | 51380772705451 |
10 | 13114132420231 |
11 | 41a6743959337 |
12 | 15797344b6547 |
13 | 74187135bc9b |
14 | 334a27d8d0a3 |
15 | 17b1de4603c1 |
hex | bed5f345687 |
13114132420231 has 2 divisors, whose sum is σ = 13114132420232. Its totient is φ = 13114132420230.
The previous prime is 13114132420201. The next prime is 13114132420313. The reversal of 13114132420231 is 13202423141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13114132420231 - 25 = 13114132420199 is a prime.
It is a super-2 number, since 2×131141324202312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13114132420231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114132420201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066210115 + 6557066210116.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066210116).
Almost surely, 213114132420231 is an apocalyptic number.
13114132420231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114132420231 is an equidigital number, since it uses as much as digits as its factorization.
13114132420231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 13114132420231 its reverse (13202423141131), we get a palindrome (26316555561362).
The spelling of 13114132420231 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred twenty thousand, two hundred thirty-one".
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