131141341041440 has 24 divisors (see below), whose sum is σ = 309821418210780. Its totient is φ = 52456536416512.

The previous prime is 131141341041397. The next prime is 131141341041479. The reversal of 131141341041440 is 44140143141131.

It can be written as a sum of positive squares in 2 ways, for example, as 128804613020944 + 2336728020496 = 11349212^2 + 1528636^2 .

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 131141341041397 and 131141341041406.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 409816690595 + ... + 409816690914.

Almost surely, 2^{131141341041440} is an apocalyptic number.

131141341041440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141341041440 is an abundant number, since it is smaller than the sum of its proper divisors (178680077169340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141341041440 is an equidigital number, since it uses as much as digits as its factorization.

131141341041440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 819633381524 (or 819633381516 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 131141341041440 its reverse (44140143141131), we get a palindrome (175281484182571).

The spelling of 131141341041440 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, forty-one thousand, four hundred forty".