Base | Representation |
---|---|
bin | 1011111011010101111110… |
… | …1011001110100111000011 |
3 | 1201102200212222122200000211 |
4 | 2332311133223032213003 |
5 | 3204330224410302433 |
6 | 43520315231454551 |
7 | 2522315423340232 |
oct | 276653753164703 |
9 | 51380788580024 |
10 | 13114140322243 |
11 | 41a6748366224 |
12 | 1579737087457 |
13 | 741872b9792c |
14 | 334a29048b19 |
15 | 17b1deec18cd |
hex | bed5face9c3 |
13114140322243 has 4 divisors (see below), whose sum is σ = 13804358233960. Its totient is φ = 12423922410528.
The previous prime is 13114140322237. The next prime is 13114140322267. The reversal of 13114140322243 is 34222304141131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13114140322243 - 29 = 13114140321731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114140322273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345108955830 + ... + 345108955867.
It is an arithmetic number, because the mean of its divisors is an integer number (3451089558490).
Almost surely, 213114140322243 is an apocalyptic number.
13114140322243 is a deficient number, since it is larger than the sum of its proper divisors (690217911717).
13114140322243 is an equidigital number, since it uses as much as digits as its factorization.
13114140322243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 690217911716.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13114140322243 its reverse (34222304141131), we get a palindrome (47336444463374).
The spelling of 13114140322243 in words is "thirteen trillion, one hundred fourteen billion, one hundred forty million, three hundred twenty-two thousand, two hundred forty-three".
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