131141403400111 has 4 divisors (see below), whose sum is σ = 141229203661672. Its totient is φ = 121053603138552.

The previous prime is 131141403400103. The next prime is 131141403400121. The reversal of 131141403400111 is 111004304141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131141403400111 - 2³ = 131141403400103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131141403400121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5043900130761 + ... + 5043900130786.

It is an arithmetic number, because the mean of its divisors is an integer number (35307300915418).

Almost surely, 2^{131141403400111} is an apocalyptic number.

131141403400111 is a deficient number, since it is larger than the sum of its proper divisors (10087800261561).

131141403400111 is a wasteful number, since it uses less digits than its factorization.

131141403400111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10087800261560.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131141403400111 its reverse (111004304141131), we get a palindrome (242145707541242).

The spelling of 131141403400111 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred three million, four hundred thousand, one hundred eleven".