131141404141130 has 8 divisors (see below), whose sum is σ = 236054527454052. Its totient is φ = 52456561656448.

The previous prime is 131141404141103. The next prime is 131141404141159. The reversal of 131141404141130 is 31141404141131.

It can be written as a sum of positive squares in 2 ways, for example, as 127718952240961 + 3422451900169 = 11301281^2 + 1849987^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131141404141093 and 131141404141102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6557070207047 + ... + 6557070207066.

Almost surely, 2^{131141404141130} is an apocalyptic number.

131141404141130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131141404141130 is a deficient number, since it is larger than the sum of its proper divisors (104913123312922).

131141404141130 is a wasteful number, since it uses less digits than its factorization.

131141404141130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13114140414120.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 131141404141130 its reverse (31141404141131), we get a palindrome (162282808282261).

Subtracting from 131141404141130 its reverse (31141404141131), we obtain a palindrome (99999999999999).

The spelling of 131141404141130 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred four million, one hundred forty-one thousand, one hundred thirty".