Base | Representation |
---|---|
bin | 10011000101010110101… |
… | …110110000101111001111 |
3 | 11122101000010022212101211 |
4 | 103011112232300233033 |
5 | 132441242022432421 |
6 | 2442242540315251 |
7 | 163514133063016 |
oct | 23052656605717 |
9 | 4571003285354 |
10 | 1311420124111 |
11 | 466196520499 |
12 | 1921b3b42b27 |
13 | 9688808b126 |
14 | 4768a17ba7d |
15 | 241a68009e1 |
hex | 13156bb0bcf |
1311420124111 has 4 divisors (see below), whose sum is σ = 1311422960512. Its totient is φ = 1311417287712.
The previous prime is 1311420123983. The next prime is 1311420124123. The reversal of 1311420124111 is 1114210241131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311420124111 - 27 = 1311420123983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311420124711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545775 + ... + 1709008.
It is an arithmetic number, because the mean of its divisors is an integer number (327855740128).
Almost surely, 21311420124111 is an apocalyptic number.
1311420124111 is a deficient number, since it is larger than the sum of its proper divisors (2836401).
1311420124111 is an equidigital number, since it uses as much as digits as its factorization.
1311420124111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2836400.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 1311420124111 its reverse (1114210241131), we get a palindrome (2425630365242).
The spelling of 1311420124111 in words is "one trillion, three hundred eleven billion, four hundred twenty million, one hundred twenty-four thousand, one hundred eleven".
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