131142040113132 has 36 divisors (see below), whose sum is σ = 331501440575760. Its totient is φ = 43713551061792.

The previous prime is 131142040113103. The next prime is 131142040113197. The reversal of 131142040113132 is 231311040241131.

131142040113132 is a `hidden beast` number, since 1 + 3 + 114 + 2 + 0 + 401 + 13 + 132 = 666.

It is a tau number, because it is divible by the number of its divisors (36).

It is a junction number, because it is equal to n+sod(n) for n = 131142040113096 and 131142040113105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15803088 + ... + 22627895.

Almost surely, 2^{131142040113132} is an apocalyptic number.

131142040113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131142040113132 is an abundant number, since it is smaller than the sum of its proper divisors (200359400462628).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142040113132 is a wasteful number, since it uses less digits than its factorization.

131142040113132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38525782 (or 38525777 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 131142040113132 its reverse (231311040241131), we get a palindrome (362453080354263).

The spelling of 131142040113132 in words is "one hundred thirty-one trillion, one hundred forty-two billion, forty million, one hundred thirteen thousand, one hundred thirty-two".