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131142114214012 = 22112980502595773
BaseRepresentation
bin11101110100010111100111…
…001000100000000001111100
3122012100001201102101210101201
4131310113213020200001330
5114142113022214322022
61142525504445145244
736423463562304166
oct3564274710400174
9565301642353351
10131142114214012
1138871070673570
121286027885b224
135823857439505
14245545293d936
151026492455127
hex7745e722007c

131142114214012 has 12 divisors (see below), whose sum is σ = 250362218045016. Its totient is φ = 59610051915440.

The previous prime is 131142114214003. The next prime is 131142114214031. The reversal of 131142114214012 is 210412411241131.

It is a super-2 number, since 2×1311421142140122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1490251297843 + ... + 1490251297930.

It is an arithmetic number, because the mean of its divisors is an integer number (20863518170418).

Almost surely, 2131142114214012 is an apocalyptic number.

It is an amenable number.

131142114214012 is a deficient number, since it is larger than the sum of its proper divisors (119220103831004).

131142114214012 is a wasteful number, since it uses less digits than its factorization.

131142114214012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2980502595788 (or 2980502595786 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 28.

Adding to 131142114214012 its reverse (210412411241131), we get a palindrome (341554525455143).

The spelling of 131142114214012 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred fourteen million, two hundred fourteen thousand, twelve".

Divisors: 1 2 4 11 22 44 2980502595773 5961005191546 11922010383092 32785528553503 65571057107006 131142114214012