Base | Representation |
---|---|
bin | 1011111011010110001111… |
… | …1110001011101111100110 |
3 | 1201102201002000021121021011 |
4 | 2332311203332023233212 |
5 | 3204330401333300402 |
6 | 43520330324412434 |
7 | 2522320260106612 |
oct | 276654376135746 |
9 | 51381060247234 |
10 | 13114212400102 |
11 | 41a6785016400 |
12 | 157975724711a |
13 | 741884ab3158 |
14 | 334a3484c342 |
15 | 17b1e64aced7 |
hex | bed63f8bbe6 |
13114212400102 has 24 divisors (see below), whose sum is σ = 21632674942368. Its totient is φ = 5958115925520.
The previous prime is 13114212400099. The next prime is 13114212400117. The reversal of 13114212400102 is 20100421241131.
It is a super-3 number, since 3×131142124001023 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12634773 + ... + 13633264.
It is an arithmetic number, because the mean of its divisors is an integer number (901361455932).
Almost surely, 213114212400102 is an apocalyptic number.
13114212400102 is a deficient number, since it is larger than the sum of its proper divisors (8518462542266).
13114212400102 is a wasteful number, since it uses less digits than its factorization.
13114212400102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26270124 (or 26270113 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 13114212400102 its reverse (20100421241131), we get a palindrome (33214633641233).
The spelling of 13114212400102 in words is "thirteen trillion, one hundred fourteen billion, two hundred twelve million, four hundred thousand, one hundred two".
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