Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …000000001010101111101 |
3 | 11122101000021220012001012 |
4 | 103011112320001111331 |
5 | 132441243133121141 |
6 | 2442243104325005 |
7 | 163514162522513 |
oct | 23052670012575 |
9 | 4571007805035 |
10 | 1311422551421 |
11 | 466197929134 |
12 | 1921b4913765 |
13 | 9688872abc8 |
14 | 4768a6104b3 |
15 | 241a6b2eceb |
hex | 13156e0157d |
1311422551421 has 2 divisors, whose sum is σ = 1311422551422. Its totient is φ = 1311422551420.
The previous prime is 1311422551403. The next prime is 1311422551511. The reversal of 1311422551421 is 1241552241131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 893996724196 + 417425827225 = 945514^2 + 646085^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311422551421 - 218 = 1311422289277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311422551921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711275710 + 655711275711.
It is an arithmetic number, because the mean of its divisors is an integer number (655711275711).
Almost surely, 21311422551421 is an apocalyptic number.
It is an amenable number.
1311422551421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311422551421 is an equidigital number, since it uses as much as digits as its factorization.
1311422551421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9600, while the sum is 32.
Adding to 1311422551421 its reverse (1241552241131), we get a palindrome (2552974792552).
The spelling of 1311422551421 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred fifty-one thousand, four hundred twenty-one".
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