Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …000000001010111011111 |
3 | 11122101000021220012011211 |
4 | 103011112320001113133 |
5 | 132441243133122034 |
6 | 2442243104325251 |
7 | 163514162523013 |
oct | 23052670012737 |
9 | 4571007805154 |
10 | 1311422551519 |
11 | 466197929213 |
12 | 1921b4913827 |
13 | 9688872ac72 |
14 | 4768a610543 |
15 | 241a6b2ed64 |
hex | 13156e015df |
1311422551519 has 2 divisors, whose sum is σ = 1311422551520. Its totient is φ = 1311422551518.
The previous prime is 1311422551511. The next prime is 1311422551541. The reversal of 1311422551519 is 9151552241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311422551519 - 23 = 1311422551511 is a prime.
It is a super-2 number, since 2×13114225515192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311422551511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711275759 + 655711275760.
It is an arithmetic number, because the mean of its divisors is an integer number (655711275760).
Almost surely, 21311422551519 is an apocalyptic number.
1311422551519 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311422551519 is an equidigital number, since it uses as much as digits as its factorization.
1311422551519 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 40.
The spelling of 1311422551519 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred fifty-one thousand, five hundred nineteen".
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