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1311423314555 = 51715428509583
BaseRepresentation
bin10011000101010110111…
…010111011101001111011
311122101000100022221212102
4103011112322323221323
5132441243332031210
62442243132534015
7163514202151424
oct23052672735173
94571010287772
101311423314555
114661982aa522
121921b502130b
1396888937373
144768a76c64b
15241a6c30ea5
hex13156ebba7b

1311423314555 has 8 divisors (see below), whose sum is σ = 1666279035072. Its totient is φ = 987424613248.

The previous prime is 1311423314533. The next prime is 1311423314581. The reversal of 1311423314555 is 5554133241131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311423314555 - 224 = 1311406537339 is a prime.

It is a super-2 number, since 2×13114233145552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7714254707 + ... + 7714254876.

It is an arithmetic number, because the mean of its divisors is an integer number (208284879384).

Almost surely, 21311423314555 is an apocalyptic number.

1311423314555 is a deficient number, since it is larger than the sum of its proper divisors (354855720517).

1311423314555 is a wasteful number, since it uses less digits than its factorization.

1311423314555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15428509605.

The product of its digits is 108000, while the sum is 38.

Adding to 1311423314555 its reverse (5554133241131), we get a palindrome (6865556555686).

The spelling of 1311423314555 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred fourteen thousand, five hundred fifty-five".

Divisors: 1 5 17 85 15428509583 77142547915 262284662911 1311423314555