Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …010111110000000110001 |
3 | 11122101000100100110002222 |
4 | 103011112322332000301 |
5 | 132441243332333314 |
6 | 2442243133050425 |
7 | 163514202221525 |
oct | 23052672760061 |
9 | 4571010313088 |
10 | 1311423324209 |
11 | 4661983067a9 |
12 | 1921b5026a15 |
13 | 9688893b88b |
14 | 4768a771d85 |
15 | 241a6c33c8e |
hex | 13156ebe031 |
1311423324209 has 2 divisors, whose sum is σ = 1311423324210. Its totient is φ = 1311423324208.
The previous prime is 1311423324137. The next prime is 1311423324221. The reversal of 1311423324209 is 9024233241131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 830564290609 + 480859033600 = 911353^2 + 693440^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311423324209 - 228 = 1311154888753 is a prime.
It is a super-2 number, since 2×13114233242092 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311423324229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711662104 + 655711662105.
It is an arithmetic number, because the mean of its divisors is an integer number (655711662105).
Almost surely, 21311423324209 is an apocalyptic number.
It is an amenable number.
1311423324209 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423324209 is an equidigital number, since it uses as much as digits as its factorization.
1311423324209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 1311423324209 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-four thousand, two hundred nine".
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