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1311423324137 is a prime number
BaseRepresentation
bin10011000101010110111…
…010111101111111101001
311122101000100100110000022
4103011112322331333221
5132441243332333022
62442243133050225
7163514202221363
oct23052672757751
94571010313008
101311423324137
11466198306743
121921b5026975
139688893b834
144768a771d33
15241a6c33c42
hex13156ebdfe9

1311423324137 has 2 divisors, whose sum is σ = 1311423324138. Its totient is φ = 1311423324136.

The previous prime is 1311423324119. The next prime is 1311423324209. The reversal of 1311423324137 is 7314233241131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 936180094096 + 375243230041 = 967564^2 + 612571^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311423324137 - 224 = 1311406546921 is a prime.

It is a super-2 number, since 2×13114233241372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311423324097 and 1311423324106.

It is not a weakly prime, because it can be changed into another prime (1311423024137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711662068 + 655711662069.

It is an arithmetic number, because the mean of its divisors is an integer number (655711662069).

Almost surely, 21311423324137 is an apocalyptic number.

It is an amenable number.

1311423324137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423324137 is an equidigital number, since it uses as much as digits as its factorization.

1311423324137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36288, while the sum is 35.

Adding to 1311423324137 its reverse (7314233241131), we get a palindrome (8625656565268).

The spelling of 1311423324137 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-four thousand, one hundred thirty-seven".