1311423324751 has 2 divisors, whose sum is σ = 1311423324752. Its totient is φ = 1311423324750.

The previous prime is 1311423324713. The next prime is 1311423324859. The reversal of 1311423324751 is 1574233241131.

It is a weak prime.

It is an emirp because it is prime and its reverse (1574233241131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311423324751 is a prime.

It is a super-2 number, since 2×1311423324751² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311423324751.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311423384751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711662375 + 655711662376.

It is an arithmetic number, because the mean of its divisors is an integer number (655711662376).

Almost surely, 2^{1311423324751} is an apocalyptic number.

1311423324751 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423324751 is an equidigital number, since it uses as much as digits as its factorization.

1311423324751 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60480, while the sum is 37.

Adding to 1311423324751 its reverse (1574233241131), we get a palindrome (2885656565882).

The spelling of 1311423324751 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-four thousand, seven hundred fifty-one".