Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …011011010010011100111 |
3 | 11122101000100120100002100 |
4 | 103011112323122103213 |
5 | 132441243400040403 |
6 | 2442243135343143 |
7 | 163514203213440 |
oct | 23052673322347 |
9 | 4571010510070 |
10 | 1311423440103 |
11 | 466198385887 |
12 | 1921b5081ab3 |
13 | 9688897c55a |
14 | 4768a7a22c7 |
15 | 241a6c582a3 |
hex | 13156eda4e7 |
1311423440103 has 24 divisors (see below), whose sum is σ = 2165930017056. Its totient is φ = 749024640000.
The previous prime is 1311423440021. The next prime is 1311423440123. The reversal of 1311423440103 is 3010443241131.
1311423440103 is a `hidden beast` number, since 1 + 3 + 114 + 2 + 3 + 440 + 103 = 666.
It is not a de Polignac number, because 1311423440103 - 218 = 1311423177959 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311423440123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4870398 + ... + 5132603.
It is an arithmetic number, because the mean of its divisors is an integer number (90247084044).
Almost surely, 21311423440103 is an apocalyptic number.
1311423440103 is a deficient number, since it is larger than the sum of its proper divisors (854506576953).
1311423440103 is a wasteful number, since it uses less digits than its factorization.
1311423440103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10005095 (or 10005092 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1311423440103 its reverse (3010443241131), we get a palindrome (4321866681234).
The spelling of 1311423440103 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, four hundred forty thousand, one hundred three".
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