131142420123821 has 2 divisors, whose sum is σ = 131142420123822. Its totient is φ = 131142420123820.

The previous prime is 131142420123751. The next prime is 131142420123823. The reversal of 131142420123821 is 128321024241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68769370852900 + 62373049270921 = 8292730^2 + 7897661^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142420123821 - 2¹⁰ = 131142420122797 is a prime.

Together with 131142420123823, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142420123823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571210061910 + 65571210061911.

It is an arithmetic number, because the mean of its divisors is an integer number (65571210061911).

Almost surely, 2^{131142420123821} is an apocalyptic number.

It is an amenable number.

131142420123821 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142420123821 is an equidigital number, since it uses as much as digits as its factorization.

131142420123821 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 35.

Adding to 131142420123821 its reverse (128321024241131), we get a palindrome (259463444364952).

The spelling of 131142420123821 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty million, one hundred twenty-three thousand, eight hundred twenty-one".