131142422220221 has 2 divisors, whose sum is σ = 131142422220222. Its totient is φ = 131142422220220.

The previous prime is 131142422220193. The next prime is 131142422220223. The reversal of 131142422220221 is 122022224241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114560309791225 + 16582112428996 = 10703285^2 + 4072114^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131142422220221 is a prime.

Together with 131142422220223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142422220223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211110110 + 65571211110111.

It is an arithmetic number, because the mean of its divisors is an integer number (65571211110111).

Almost surely, 2^{131142422220221} is an apocalyptic number.

It is an amenable number.

131142422220221 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142422220221 is an equidigital number, since it uses as much as digits as its factorization.

131142422220221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 131142422220221 its reverse (122022224241131), we get a palindrome (253164646461352).

The spelling of 131142422220221 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, two hundred twenty thousand, two hundred twenty-one".