Base | Representation |
---|---|
bin | 10011000101010111010… |
… | …100111010101111010101 |
3 | 11122101000211011001011111 |
4 | 103011113110322233111 |
5 | 132441302103022144 |
6 | 2442243534535021 |
7 | 163514314102444 |
oct | 23052724725725 |
9 | 4571024131144 |
10 | 1311430126549 |
11 | 4661a1132474 |
12 | 1921b7367471 |
13 | 9688a180b2a |
14 | 4768b622d5b |
15 | 241a7629534 |
hex | 1315753abd5 |
1311430126549 has 2 divisors, whose sum is σ = 1311430126550. Its totient is φ = 1311430126548.
The previous prime is 1311430126453. The next prime is 1311430126577. The reversal of 1311430126549 is 9456210341131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1144059134449 + 167370992100 = 1069607^2 + 409110^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311430126549 - 29 = 1311430126037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311430126949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655715063274 + 655715063275.
It is an arithmetic number, because the mean of its divisors is an integer number (655715063275).
Almost surely, 21311430126549 is an apocalyptic number.
It is an amenable number.
1311430126549 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311430126549 is an equidigital number, since it uses as much as digits as its factorization.
1311430126549 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 1311430126549 in words is "one trillion, three hundred eleven billion, four hundred thirty million, one hundred twenty-six thousand, five hundred forty-nine".
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