131143113044310 has 32 divisors (see below), whose sum is σ = 314755111883520. Its totient is φ = 34970203414368.

The previous prime is 131143113044263. The next prime is 131143113044329. The reversal of 131143113044310 is 13440311341131.

It is a super-2 number, since 2×131143113044310² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80012530 + ... + 81635109.

It is an arithmetic number, because the mean of its divisors is an integer number (9836097246360).

Almost surely, 2^{131143113044310} is an apocalyptic number.

131143113044310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131143113044310 is an abundant number, since it is smaller than the sum of its proper divisors (183611998839210).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143113044310 is a wasteful number, since it uses less digits than its factorization.

131143113044310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161674692.

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 131143113044310 its reverse (13440311341131), we get a palindrome (144583424385441).

The spelling of 131143113044310 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirteen million, forty-four thousand, three hundred ten".