13114330420133 has 2 divisors, whose sum is σ = 13114330420134. Its totient is φ = 13114330420132.

The previous prime is 13114330420129. The next prime is 13114330420153. The reversal of 13114330420133 is 33102403341131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12873586128484 + 240744291649 = 3587978^2 + 490657^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114330420133 - 2² = 13114330420129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114330420096 and 13114330420105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114330420153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557165210066 + 6557165210067.

It is an arithmetic number, because the mean of its divisors is an integer number (6557165210067).

Almost surely, 2^{13114330420133} is an apocalyptic number.

It is an amenable number.

13114330420133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114330420133 is an equidigital number, since it uses as much as digits as its factorization.

13114330420133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 13114330420133 its reverse (33102403341131), we get a palindrome (46216733761264).

The spelling of 13114330420133 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty million, four hundred twenty thousand, one hundred thirty-three".