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1311433156135 = 5377088827871
BaseRepresentation
bin10011000101010111100…
…000011110011000100111
311122101001000211221222101
4103011113200132120213
5132441303341444020
62442244123512531
7163514351621164
oct23052740363047
94571030757871
101311433156135
114661a2911663
121921b8388747
139688a9a1a9b
144768bbb106b
15241a7a2700a
hex1315781e627

1311433156135 has 8 divisors (see below), whose sum is σ = 1616252754816. Its totient is φ = 1020791213280.

The previous prime is 1311433156051. The next prime is 1311433156141. The reversal of 1311433156135 is 5316513341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1311433156135 - 225 = 1311399601703 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (37).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311433156094 and 1311433156103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3544413751 + ... + 3544414120.

It is an arithmetic number, because the mean of its divisors is an integer number (202031594352).

Almost surely, 21311433156135 is an apocalyptic number.

1311433156135 is a deficient number, since it is larger than the sum of its proper divisors (304819598681).

1311433156135 is an equidigital number, since it uses as much as digits as its factorization.

1311433156135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7088827913.

The product of its digits is 48600, while the sum is 37.

Adding to 1311433156135 its reverse (5316513341131), we get a palindrome (6627946497266).

The spelling of 1311433156135 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, one hundred fifty-six thousand, one hundred thirty-five".

Divisors: 1 5 37 185 7088827871 35444139355 262286631227 1311433156135