13114334000001 has 8 divisors (see below), whose sum is σ = 18830838564160. Its totient is φ = 8070359384592.

The previous prime is 13114333999993. The next prime is 13114334000011. The reversal of 13114334000001 is 10000043341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13114334000001 - 2³ = 13114333999993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114334000011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168132487141 + ... + 168132487218.

It is an arithmetic number, because the mean of its divisors is an integer number (2353854820520).

Almost surely, 2^{13114334000001} is an apocalyptic number.

It is an amenable number.

13114334000001 is a deficient number, since it is larger than the sum of its proper divisors (5716504564159).

13114334000001 is a wasteful number, since it uses less digits than its factorization.

13114334000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 336264974375.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13114334000001 its reverse (10000043341131), we get a palindrome (23114377341132).

The spelling of 13114334000001 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, one", and thus it is an aban number.