1311434062411 has 4 divisors (see below), whose sum is σ = 1430655340824. Its totient is φ = 1192212784000.

The previous prime is 1311434062387. The next prime is 1311434062439. The reversal of 1311434062411 is 1142604341131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311434062411 - 2¹³ = 1311434054219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311434062451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59610639190 + ... + 59610639211.

It is an arithmetic number, because the mean of its divisors is an integer number (357663835206).

Almost surely, 2^{1311434062411} is an apocalyptic number.

1311434062411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1311434062411 is a deficient number, since it is larger than the sum of its proper divisors (119221278413).

1311434062411 is a wasteful number, since it uses less digits than its factorization.

1311434062411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119221278412.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 1311434062411 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, sixty-two thousand, four hundred eleven".