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1311434102455 = 5619423726689
BaseRepresentation
bin10011000101010111100…
…100000101011010110111
311122101001002122001002021
4103011113210011122313
5132441304112234310
62442244200054011
7163514362642141
oct23052744053267
94571032561067
101311434102455
114661a33a8644
121921b8764307
139688ac43739
144768bd79c91
15241a7b625da
hex131579056b7

1311434102455 has 8 divisors (see below), whose sum is σ = 1576263286800. Its totient is φ = 1047452372736.

The previous prime is 1311434102441. The next prime is 1311434102471. The reversal of 1311434102455 is 5542014341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311434102455 - 211 = 1311434100407 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311434102455.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 211860250 + ... + 211866439.

It is an arithmetic number, because the mean of its divisors is an integer number (197032910850).

Almost surely, 21311434102455 is an apocalyptic number.

1311434102455 is a deficient number, since it is larger than the sum of its proper divisors (264829184345).

1311434102455 is an equidigital number, since it uses as much as digits as its factorization.

1311434102455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 423727313.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 1311434102455 its reverse (5542014341131), we get a palindrome (6853448443586).

The spelling of 1311434102455 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, one hundred two thousand, four hundred fifty-five".

Divisors: 1 5 619 3095 423726689 2118633445 262286820491 1311434102455