13114341323261 has 2 divisors, whose sum is σ = 13114341323262. Its totient is φ = 13114341323260.

The previous prime is 13114341323257. The next prime is 13114341323263. The reversal of 13114341323261 is 16232314341131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7766638823161 + 5347702500100 = 2786869^2 + 2312510^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114341323261 - 2² = 13114341323257 is a prime.

Together with 13114341323263, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114341323263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557170661630 + 6557170661631.

It is an arithmetic number, because the mean of its divisors is an integer number (6557170661631).

Almost surely, 2^{13114341323261} is an apocalyptic number.

It is an amenable number.

13114341323261 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114341323261 is an equidigital number, since it uses as much as digits as its factorization.

13114341323261 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 35.

Adding to 13114341323261 its reverse (16232314341131), we get a palindrome (29346655664392).

The spelling of 13114341323261 in words is "thirteen trillion, one hundred fourteen billion, three hundred forty-one million, three hundred twenty-three thousand, two hundred sixty-one".