13114400301310 has 256 divisors, whose sum is σ = 31133318381568. Its totient is φ = 3858825484800.

The previous prime is 13114400301259. The next prime is 13114400301311. The reversal of 13114400301310 is 1310300441131.

It is a super-2 number, since 2×13114400301310² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114400301311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 164687064 + ... + 164766676.

It is an arithmetic number, because the mean of its divisors is an integer number (121614524928).

Almost surely, 2^{13114400301310} is an apocalyptic number.

13114400301310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13114400301310 is an abundant number, since it is smaller than the sum of its proper divisors (18018918080258).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114400301310 is a wasteful number, since it uses less digits than its factorization.

13114400301310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79839.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13114400301310 its reverse (1310300441131), we get a palindrome (14424700742441).

The spelling of 13114400301310 in words is "thirteen trillion, one hundred fourteen billion, four hundred million, three hundred one thousand, three hundred ten".