Base | Representation |
---|---|
bin | 1011111011010110111101… |
… | …1010101011101001111111 |
3 | 1201102201120101121020100111 |
4 | 2332311233122223221333 |
5 | 3204331300012421343 |
6 | 43520401344210451 |
7 | 2522325111210211 |
oct | 276655732535177 |
9 | 51381511536314 |
10 | 13114404420223 |
11 | 41a6873448a17 |
12 | 15797ab609a27 |
13 | 7418b5805222 |
14 | 334a521545b1 |
15 | 17b20828cc9d |
hex | bed6f6aba7f |
13114404420223 has 2 divisors, whose sum is σ = 13114404420224. Its totient is φ = 13114404420222.
The previous prime is 13114404420203. The next prime is 13114404420251. The reversal of 13114404420223 is 32202440441131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114404420223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114404420203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557202210111 + 6557202210112.
It is an arithmetic number, because the mean of its divisors is an integer number (6557202210112).
Almost surely, 213114404420223 is an apocalyptic number.
13114404420223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114404420223 is an equidigital number, since it uses as much as digits as its factorization.
13114404420223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 13114404420223 its reverse (32202440441131), we get a palindrome (45316844861354).
The spelling of 13114404420223 in words is "thirteen trillion, one hundred fourteen billion, four hundred four million, four hundred twenty thousand, two hundred twenty-three".
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