13114413131 has 2 divisors, whose sum is σ = 13114413132. Its totient is φ = 13114413130.

The previous prime is 13114413127. The next prime is 13114413133. The reversal of 13114413131 is 13131441131.

It is a strong prime.

It is an emirp because it is prime and its reverse (13131441131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13114413131 - 2² = 13114413127 is a prime.

It is a super-2 number, since 2×13114413131² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13114413133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114413097 and 13114413106.

It is not a weakly prime, because it can be changed into another prime (13114413133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557206565 + 6557206566.

It is an arithmetic number, because the mean of its divisors is an integer number (6557206566).

Almost surely, 2^13114413131 is an apocalyptic number.

13114413131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114413131 is an equidigital number, since it uses as much as digits as its factorization.

13114413131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 23.

Adding to 13114413131 its reverse (13131441131), we get a palindrome (26245854262).

The spelling of 13114413131 in words is "thirteen billion, one hundred fourteen million, four hundred thirteen thousand, one hundred thirty-one".