1311441356140 has 24 divisors (see below), whose sum is σ = 2821198236192. Its totient is φ = 511781992320.

The previous prime is 1311441356129. The next prime is 1311441356171. The reversal of 1311441356140 is 416531441131.

It is a junction number, because it is equal to n+sod(n) for n = 1311441356096 and 1311441356105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 799658544 + ... + 799660183.

It is an arithmetic number, because the mean of its divisors is an integer number (117549926508).

Almost surely, 2^{1311441356140} is an apocalyptic number.

1311441356140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311441356140 is an abundant number, since it is smaller than the sum of its proper divisors (1509756880052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311441356140 is a wasteful number, since it uses less digits than its factorization.

1311441356140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1599318777 (or 1599318775 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 1311441356140 its reverse (416531441131), we get a palindrome (1727972797271).

The spelling of 1311441356140 in words is "one trillion, three hundred eleven billion, four hundred forty-one million, three hundred fifty-six thousand, one hundred forty".