Base | Representation |
---|---|
bin | 11000011011010111… |
… | …01000000101111111 |
3 | 1020211222010200112012 |
4 | 30031223220011333 |
5 | 203324244121421 |
6 | 10005200001435 |
7 | 642662630051 |
oct | 141553500577 |
9 | 36758120465 |
10 | 13114442111 |
11 | 561a840511 |
12 | 266000027b |
13 | 1310000c24 |
14 | 8c5a398d1 |
15 | 51b50a95b |
hex | 30dae817f |
13114442111 has 4 divisors (see below), whose sum is σ = 13126921224. Its totient is φ = 13101963000.
The previous prime is 13114442071. The next prime is 13114442113. The reversal of 13114442111 is 11124441131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11124441131 = 9521 ⋅1168411.
It is a cyclic number.
It is not a de Polignac number, because 13114442111 - 222 = 13110247807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114442113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6237980 + ... + 6240081.
It is an arithmetic number, because the mean of its divisors is an integer number (3281730306).
Almost surely, 213114442111 is an apocalyptic number.
13114442111 is a deficient number, since it is larger than the sum of its proper divisors (12479113).
13114442111 is a wasteful number, since it uses less digits than its factorization.
13114442111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12479112.
The product of its digits is 384, while the sum is 23.
Adding to 13114442111 its reverse (11124441131), we get a palindrome (24238883242).
The spelling of 13114442111 in words is "thirteen billion, one hundred fourteen million, four hundred forty-two thousand, one hundred eleven".
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