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1311450221369 is a prime number
BaseRepresentation
bin10011000101011000100…
…001100100101100111001
311122101002012221222002002
4103011120201210230321
5132441322224040434
62442245533350345
7163514646645101
oct23053041445471
94571065858062
101311450221369
11466201507a62
121922020383b5
1396891398462
1447690174201
15241a929857e
hex13158864b39

1311450221369 has 2 divisors, whose sum is σ = 1311450221370. Its totient is φ = 1311450221368.

The previous prime is 1311450221239. The next prime is 1311450221371. The reversal of 1311450221369 is 9631220541131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 867947499769 + 443502721600 = 931637^2 + 665960^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311450221369 is a prime.

It is a super-3 number, since 3×13114502213693 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1311450221371, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1311450221399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655725110684 + 655725110685.

It is an arithmetic number, because the mean of its divisors is an integer number (655725110685).

Almost surely, 21311450221369 is an apocalyptic number.

It is an amenable number.

1311450221369 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311450221369 is an equidigital number, since it uses as much as digits as its factorization.

1311450221369 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 38.

The spelling of 1311450221369 in words is "one trillion, three hundred eleven billion, four hundred fifty million, two hundred twenty-one thousand, three hundred sixty-nine".