Base | Representation |
---|---|
bin | 10011000101011100101… |
… | …101110101000110000111 |
3 | 11122101021010021200101001 |
4 | 103011130231311012013 |
5 | 132441443224334421 |
6 | 2442300524514131 |
7 | 163516462451542 |
oct | 23053455650607 |
9 | 4571233250331 |
10 | 1311520543111 |
11 | 4662381787a9 |
12 | 1922216ab947 |
13 | 968a2b1a55c |
14 | 4769963b859 |
15 | 241b0539691 |
hex | 1315cb75187 |
1311520543111 has 2 divisors, whose sum is σ = 1311520543112. Its totient is φ = 1311520543110.
The previous prime is 1311520543043. The next prime is 1311520543117. The reversal of 1311520543111 is 1113450251131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311520543111 - 215 = 1311520510343 is a prime.
It is a super-2 number, since 2×13115205431112 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1311520543111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311520543117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655760271555 + 655760271556.
It is an arithmetic number, because the mean of its divisors is an integer number (655760271556).
Almost surely, 21311520543111 is an apocalyptic number.
1311520543111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311520543111 is an equidigital number, since it uses as much as digits as its factorization.
1311520543111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 28.
Adding to 1311520543111 its reverse (1113450251131), we get a palindrome (2424970794242).
The spelling of 1311520543111 in words is "one trillion, three hundred eleven billion, five hundred twenty million, five hundred forty-three thousand, one hundred eleven".
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