Base | Representation |
---|---|
bin | 11000011011011110… |
… | …01001010011000111 |
3 | 1020212000212112212122 |
4 | 30031233021103013 |
5 | 203330013131201 |
6 | 10005231440155 |
7 | 643003521302 |
oct | 141557112307 |
9 | 36760775778 |
10 | 13115364551 |
11 | 5620310563 |
12 | 266038605b |
13 | 1310264a53 |
14 | 8c5bd9b39 |
15 | 51b63de1b |
hex | 30dbc94c7 |
13115364551 has 2 divisors, whose sum is σ = 13115364552. Its totient is φ = 13115364550.
The previous prime is 13115364541. The next prime is 13115364553. The reversal of 13115364551 is 15546351131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13115364551 is a prime.
Together with 13115364553, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13115364553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557682275 + 6557682276.
It is an arithmetic number, because the mean of its divisors is an integer number (6557682276).
Almost surely, 213115364551 is an apocalyptic number.
13115364551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13115364551 is an equidigital number, since it uses as much as digits as its factorization.
13115364551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27000, while the sum is 35.
The spelling of 13115364551 in words is "thirteen billion, one hundred fifteen million, three hundred sixty-four thousand, five hundred fifty-one".
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