Base | Representation |
---|---|
bin | 10011000101011110000… |
… | …101001110101011010111 |
3 | 11122101022201101200210011 |
4 | 103011132011032223113 |
5 | 132442020111020143 |
6 | 2442303103541051 |
7 | 163520161264426 |
oct | 23053605165327 |
9 | 4571281350704 |
10 | 1311543454423 |
11 | 46624a0a7374 |
12 | 1922292ba787 |
13 | 968a77acb47 |
14 | 4769c6c32bd |
15 | 241b2562e9d |
hex | 1315e14ead7 |
1311543454423 has 2 divisors, whose sum is σ = 1311543454424. Its totient is φ = 1311543454422.
The previous prime is 1311543454421. The next prime is 1311543454517. The reversal of 1311543454423 is 3244543451131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311543454423 - 21 = 1311543454421 is a prime.
Together with 1311543454421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311543454421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655771727211 + 655771727212.
It is an arithmetic number, because the mean of its divisors is an integer number (655771727212).
Almost surely, 21311543454423 is an apocalyptic number.
1311543454423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311543454423 is an equidigital number, since it uses as much as digits as its factorization.
1311543454423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 345600, while the sum is 40.
The spelling of 1311543454423 in words is "one trillion, three hundred eleven billion, five hundred forty-three million, four hundred fifty-four thousand, four hundred twenty-three".
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