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1311543523135 = 5312272953907
BaseRepresentation
bin10011000101011110000…
…101011111011100111111
311122101022201112012001001
4103011132011133130333
5132442020120220020
62442303105231131
7163520162001646
oct23053605373477
94571281465031
101311543523135
1146624a143a5a
121922293324a7
13968a78051c1
144769c70035d
15241b257850a
hex1315e15f73f

1311543523135 has 12 divisors (see below), whose sum is σ = 1626259383864. Its totient is φ = 1015388530320.

The previous prime is 1311543523127. The next prime is 1311543523201. The reversal of 1311543523135 is 5313253451131.

It is not a de Polignac number, because 1311543523135 - 23 = 1311543523127 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311543523094 and 1311543523103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 136472149 + ... + 136481758.

It is an arithmetic number, because the mean of its divisors is an integer number (135521615322).

Almost surely, 21311543523135 is an apocalyptic number.

1311543523135 is a deficient number, since it is larger than the sum of its proper divisors (314715860729).

1311543523135 is an equidigital number, since it uses as much as digits as its factorization.

1311543523135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 272953974 (or 272953943 counting only the distinct ones).

The product of its digits is 81000, while the sum is 37.

Adding to 1311543523135 its reverse (5313253451131), we get a palindrome (6624796974266).

The spelling of 1311543523135 in words is "one trillion, three hundred eleven billion, five hundred forty-three million, five hundred twenty-three thousand, one hundred thirty-five".

Divisors: 1 5 31 155 961 4805 272953907 1364769535 8461571117 42307855585 262308704627 1311543523135