Base | Representation |
---|---|
bin | 1011111011011111110010… |
… | …1111011000000011110101 |
3 | 1201102221200122002010122200 |
4 | 2332313330233120003311 |
5 | 3204401124002314222 |
6 | 43521432523215113 |
7 | 2522440631402235 |
oct | 276677457300365 |
9 | 51387618063580 |
10 | 13116775432437 |
11 | 41a787a861546 |
12 | 157a151677499 |
13 | 741ba2ab1831 |
14 | 334bd8dc9cc5 |
15 | 17b2e64d9eac |
hex | bedfcbd80f5 |
13116775432437 has 12 divisors (see below), whose sum is σ = 19770212246304. Its totient is φ = 8364320565480.
The previous prime is 13116775432427. The next prime is 13116775432441. The reversal of 13116775432437 is 73423457761131.
13116775432437 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 6 + 77 + 543 + 24 + 3 + 7 = 666.
It is not a de Polignac number, because 13116775432437 - 24 = 13116775432421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13116775432427) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31683032239 + ... + 31683032652.
It is an arithmetic number, because the mean of its divisors is an integer number (1647517687192).
Almost surely, 213116775432437 is an apocalyptic number.
It is an amenable number.
13116775432437 is a deficient number, since it is larger than the sum of its proper divisors (6653436813867).
13116775432437 is a wasteful number, since it uses less digits than its factorization.
13116775432437 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63366064920 (or 63366064917 counting only the distinct ones).
The product of its digits is 8890560, while the sum is 54.
The spelling of 13116775432437 in words is "thirteen trillion, one hundred sixteen billion, seven hundred seventy-five million, four hundred thirty-two thousand, four hundred thirty-seven".
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