Base | Representation |
---|---|
bin | 1011111011100101100011… |
… | …0100100110011000011010 |
3 | 1201110002200022000211100120 |
4 | 2332321120310212120122 |
5 | 3204412304444240230 |
6 | 43522250111214110 |
7 | 2522524130533005 |
oct | 276713064463032 |
9 | 51402608024316 |
10 | 13118320305690 |
11 | 41a84a29006a6 |
12 | 157a502b17336 |
13 | 74208ab85812 |
14 | 334d0425053c |
15 | 17b386e4a310 |
hex | bee58d2661a |
13118320305690 has 64 divisors (see below), whose sum is σ = 32587852556160. Its totient is φ = 3375700025600.
The previous prime is 13118320305667. The next prime is 13118320305709. The reversal of 13118320305690 is 9650302381131.
It is a super-2 number, since 2×131183203056902 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2664261 + ... + 5773640.
It is an arithmetic number, because the mean of its divisors is an integer number (509185196190).
Almost surely, 213118320305690 is an apocalyptic number.
13118320305690 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13118320305690 is an abundant number, since it is smaller than the sum of its proper divisors (19469532250470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13118320305690 is a wasteful number, since it uses less digits than its factorization.
13118320305690 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8439727.
The product of its (nonzero) digits is 116640, while the sum is 42.
The spelling of 13118320305690 in words is "thirteen trillion, one hundred eighteen billion, three hundred twenty million, three hundred five thousand, six hundred ninety".
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