Base | Representation |
---|---|
bin | 10011000101110010010… |
… | …111011011100010111101 |
3 | 11122102012102202112001110 |
4 | 103011302113123202331 |
5 | 132443214221120140 |
6 | 2442400542032233 |
7 | 163531463025312 |
oct | 23056227334275 |
9 | 4572172675043 |
10 | 1311883770045 |
11 | 466404207552 |
12 | 192303278679 |
13 | 96930155034 |
14 | 476d198cd09 |
15 | 241d2387380 |
hex | 131725db8bd |
1311883770045 has 16 divisors (see below), whose sum is σ = 2104641424512. Its totient is φ = 697795546560.
The previous prime is 1311883769983. The next prime is 1311883770073. The reversal of 1311883770045 is 5400773881131.
It is not a de Polignac number, because 1311883770045 - 236 = 1243164293309 is a prime.
It is a super-2 number, since 2×13118837700452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311883769976 and 1311883770003.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117231561 + ... + 117242750.
It is an arithmetic number, because the mean of its divisors is an integer number (131540089032).
Almost surely, 21311883770045 is an apocalyptic number.
1311883770045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1311883770045 is a deficient number, since it is larger than the sum of its proper divisors (792757654467).
1311883770045 is a wasteful number, since it uses less digits than its factorization.
1311883770045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 234474692.
The product of its (nonzero) digits is 564480, while the sum is 48.
The spelling of 1311883770045 in words is "one trillion, three hundred eleven billion, eight hundred eighty-three million, seven hundred seventy thousand, forty-five".
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