1312000313333 has 4 divisors (see below), whose sum is σ = 1312005918720. Its totient is φ = 1311994707948.

The previous prime is 1312000313303. The next prime is 1312000313359. The reversal of 1312000313333 is 3333130002131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312000313333 - 2¹⁰ = 1312000312309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312000313299 and 1312000313308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312000313303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2435573 + ... + 2925066.

It is an arithmetic number, because the mean of its divisors is an integer number (328001479680).

Almost surely, 2^{1312000313333} is an apocalyptic number.

It is an amenable number.

1312000313333 is a deficient number, since it is larger than the sum of its proper divisors (5605387).

1312000313333 is an equidigital number, since it uses as much as digits as its factorization.

1312000313333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5605386.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1312000313333 its reverse (3333130002131), we get a palindrome (4645130315464).

The spelling of 1312000313333 in words is "one trillion, three hundred twelve billion, three hundred thirteen thousand, three hundred thirty-three".