Base | Representation |
---|---|
bin | 10011000101111001011… |
… | …010110111011000011001 |
3 | 11122102111200102212022211 |
4 | 103011321122313120121 |
5 | 132443440020023001 |
6 | 2442420410315121 |
7 | 163534430636551 |
oct | 23057132673031 |
9 | 4572450385284 |
10 | 1312002111001 |
11 | 466464a9589a |
12 | 192336a28aa1 |
13 | 9694b81aa7a |
14 | 47703596161 |
15 | 241dc961351 |
hex | 131796b7619 |
1312002111001 has 2 divisors, whose sum is σ = 1312002111002. Its totient is φ = 1312002111000.
The previous prime is 1312002110927. The next prime is 1312002111029. The reversal of 1312002111001 is 1001112002131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1288270400400 + 23731710601 = 1135020^2 + 154051^2 .
It is an emirp because it is prime and its reverse (1001112002131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312002111001 - 229 = 1311465240089 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312002111041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656001055500 + 656001055501.
It is an arithmetic number, because the mean of its divisors is an integer number (656001055501).
Almost surely, 21312002111001 is an apocalyptic number.
It is an amenable number.
1312002111001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312002111001 is an equidigital number, since it uses as much as digits as its factorization.
1312002111001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1312002111001 its reverse (1001112002131), we get a palindrome (2313114113132).
The spelling of 1312002111001 in words is "one trillion, three hundred twelve billion, two million, one hundred eleven thousand, one".
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