Base | Representation |
---|---|
bin | 10011000101111001011… |
… | …010110111011111000000 |
3 | 11122102111200102212220111 |
4 | 103011321122313133000 |
5 | 132443440020031144 |
6 | 2442420410321104 |
7 | 163534430641024 |
oct | 23057132673700 |
9 | 4572450385814 |
10 | 1312002111424 |
11 | 466464a96144 |
12 | 192336a29194 |
13 | 9694b81b014 |
14 | 47703596384 |
15 | 241dc961534 |
hex | 131796b77c0 |
1312002111424 has 14 divisors (see below), whose sum is σ = 2603504189984. Its totient is φ = 656001055680.
The previous prime is 1312002111389. The next prime is 1312002111437. The reversal of 1312002111424 is 4241112002131.
It is a super-2 number, since 2×13120021114242 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312002111395 and 1312002111404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10250016432 + ... + 10250016559.
Almost surely, 21312002111424 is an apocalyptic number.
It is an amenable number.
1312002111424 is a deficient number, since it is larger than the sum of its proper divisors (1291502078560).
1312002111424 is an equidigital number, since it uses as much as digits as its factorization.
1312002111424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20500033003 (or 20500032993 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 1312002111424 its reverse (4241112002131), we get a palindrome (5553114113555).
The spelling of 1312002111424 in words is "one trillion, three hundred twelve billion, two million, one hundred eleven thousand, four hundred twenty-four".
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