Search a number
-
+
1312002111424 = 2620500032991
BaseRepresentation
bin10011000101111001011…
…010110111011111000000
311122102111200102212220111
4103011321122313133000
5132443440020031144
62442420410321104
7163534430641024
oct23057132673700
94572450385814
101312002111424
11466464a96144
12192336a29194
139694b81b014
1447703596384
15241dc961534
hex131796b77c0

1312002111424 has 14 divisors (see below), whose sum is σ = 2603504189984. Its totient is φ = 656001055680.

The previous prime is 1312002111389. The next prime is 1312002111437. The reversal of 1312002111424 is 4241112002131.

It is a super-2 number, since 2×13120021114242 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1312002111395 and 1312002111404.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10250016432 + ... + 10250016559.

Almost surely, 21312002111424 is an apocalyptic number.

It is an amenable number.

1312002111424 is a deficient number, since it is larger than the sum of its proper divisors (1291502078560).

1312002111424 is an equidigital number, since it uses as much as digits as its factorization.

1312002111424 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20500033003 (or 20500032993 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1312002111424 its reverse (4241112002131), we get a palindrome (5553114113555).

The spelling of 1312002111424 in words is "one trillion, three hundred twelve billion, two million, one hundred eleven thousand, four hundred twenty-four".

Divisors: 1 2 4 8 16 32 64 20500032991 41000065982 82000131964 164000263928 328000527856 656001055712 1312002111424