131201001210413 has 2 divisors, whose sum is σ = 131201001210414. Its totient is φ = 131201001210412.

The previous prime is 131201001210403. The next prime is 131201001210427. The reversal of 131201001210413 is 314012100102131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130092775495684 + 1108225714729 = 11405822^2 + 1052723^2 .

It is an emirp because it is prime and its reverse (314012100102131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131201001210413 - 2²² = 131200997016109 is a prime.

It is a super-2 number, since 2×131201001210413² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201001210403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600500605206 + 65600500605207.

It is an arithmetic number, because the mean of its divisors is an integer number (65600500605207).

Almost surely, 2^{131201001210413} is an apocalyptic number.

It is an amenable number.

131201001210413 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201001210413 is an equidigital number, since it uses as much as digits as its factorization.

131201001210413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131201001210413 its reverse (314012100102131), we get a palindrome (445213101312544).

The spelling of 131201001210413 in words is "one hundred thirty-one trillion, two hundred one billion, one million, two hundred ten thousand, four hundred thirteen".