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13120114120000 = 265410110193187
BaseRepresentation
bin1011111011101100001110…
…1111011101010101000000
31201110021022022102000222121
42332323003233131111000
53204424443203320000
643523144111014024
72522616441645226
oct276730357352500
951407268360877
1013120114120000
1141a923341a968
12157a92380a314
137422b56bb1c4
14335034596b16
1517b43e680b1a
hexbeec3bdd540

13120114120000 has 280 divisors, whose sum is σ = 32898296550240. Its totient is φ = 5189356800000.

The previous prime is 13120114119961. The next prime is 13120114120021. The reversal of 13120114120000 is 2141102131.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4116758407 + ... + 4116761593.

Almost surely, 213120114120000 is an apocalyptic number.

13120114120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13120114120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16449148275120).

13120114120000 is an abundant number, since it is smaller than the sum of its proper divisors (19778182430240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120114120000 is a wasteful number, since it uses less digits than its factorization.

13120114120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4339 (or 4314 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13120114120000 its reverse (2141102131), we get a palindrome (13122255222131).

The spelling of 13120114120000 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, one hundred twenty thousand".