131201142401020 has 24 divisors (see below), whose sum is σ = 275548375013184. Its totient is φ = 52475509156416.

The previous prime is 131201142400981. The next prime is 131201142401033. The reversal of 131201142401020 is 20104241102131.

It is a super-3 number, since 3×131201142401020³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131201142400982 and 131201142401000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309020307 + ... + 309444586.

It is an arithmetic number, because the mean of its divisors is an integer number (11481182292216).

Almost surely, 2^{131201142401020} is an apocalyptic number.

131201142401020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131201142401020 is an abundant number, since it is smaller than the sum of its proper divisors (144347232612164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201142401020 is a wasteful number, since it uses less digits than its factorization.

131201142401020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 618475509 (or 618475507 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 131201142401020 its reverse (20104241102131), we get a palindrome (151305383503151).

The spelling of 131201142401020 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-two million, four hundred one thousand, twenty".